Tokenizing a string using c /c++

Below is the code for c/c++ this a function works for me in c++. If any problem comment below. 

the string str[] variable string is declared out side of function passed to function to store the tokens in the string array.remember to allocate sufficient or more space

Required parameters for function : char str[],string s[],const char t

1 parameter: str[] is the string which you wanted to tokenize.

2 parameter :s[] is string arrray used to store the token.Declare it before function passed;

3 parameter:  t is char character at which the string should be tokenize();

Return value: none 

look function and sample code below.

Function:

void tokenize(char str[],string s[],const char t){int i=0;

    string token;int j=0;int len=strlen(str);

    for(int i=0;i< len;i++){

	    if (str[i]== t ){

		    s[j]=token;j++;token=" ";

	    }else{token.push_back(str[i]);}

	    if (i==len-1){s[j]=token;}

    }

}

sample code for testing(c++)

#include <iostream>
#include <cstring>
using namespace std;
void tokenize(const char str[],string s[],const char t){int i=0;

	string token;int j=0;int len=strlen(str);

	for(int i=0;i<len;i++){

		if (str[i]== t ){

			s[j]=token;j++;token="";

		}else{
            token.push_back(str[i]);}
		if (i==len-1){s[j]=token;}
	}

}
void printA(string s[],int n){
	for(int i=0;i<n;i++){
		cout<<s[i]<<'\n';
	}}
int main(int arg,char**argv){
	string str="it is a beautiful dog I have ever seen";
	string s[9];
	tokenize(str.c_str(),s,' ');
	printA(s,9);
	return 0;}

Output

it
is
a
beautiful
dog
I
have
ever
seen

Press ENTER or type command to continue